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X^2+12X^2-60=0
We add all the numbers together, and all the variables
13X^2-60=0
a = 13; b = 0; c = -60;
Δ = b2-4ac
Δ = 02-4·13·(-60)
Δ = 3120
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3120}=\sqrt{16*195}=\sqrt{16}*\sqrt{195}=4\sqrt{195}$$X_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-4\sqrt{195}}{2*13}=\frac{0-4\sqrt{195}}{26} =-\frac{4\sqrt{195}}{26} =-\frac{2\sqrt{195}}{13} $$X_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+4\sqrt{195}}{2*13}=\frac{0+4\sqrt{195}}{26} =\frac{4\sqrt{195}}{26} =\frac{2\sqrt{195}}{13} $
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